y^2+4y+16=13

Solution for y^2+4y+16=13 equation:

Simplifying
y2 + 4y + 16 = 13

Reorder the terms:
16 + 4y + y2 = 13

Solving
16 + 4y + y2 = 13

Solving for variable 'y'.

Reorder the terms:
16 + -13 + 4y + y2 = 13 + -13

Combine like terms: 16 + -13 = 3
3 + 4y + y2 = 13 + -13

Combine like terms: 13 + -13 = 0
3 + 4y + y2 = 0

Factor a trinomial.
(3 + y)(1 + y) = 0

Subproblem 1
Set the factor '(3 + y)' equal to zero and attempt to solve:

Simplifying
3 + y = 0

Solving
3 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + y = 0 + -3
y = 0 + -3

Combine like terms: 0 + -3 = -3
y = -3

Simplifying
y = -3
Subproblem 2
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Solution
y = {-3, -1}